C/c++ 怎么按位拷贝呢

#include <stdio.h>
int main()
{
    struct st_header
    {
       unsigned short ver;
       unsigned short ping;
       unsigned short mark;
    };

    char  pdata[100] = "12345678910";
    char  *p = pdata;
    int   i = 0;

    struct st_header  test = {
    0,
    0,
    0
    };

    while(i<2 || *p=='\0')
    {
        test.ver = test.ver*10+(*p-'0');
        p++    ;
        i++;
    }


    test.ping = *p-'0';
    p++;

    i = 0;
    while(i<2 || *p=='\0')
    {
        test.mark = test.mark*10+(*p-'0');
        p++    ;
        i++ ;
    }


    printf("ver=%d\nping=%d\nmark=%d\n",test.ver,test.ping,test.mark);


    return 0;
}

------解决方案--------------------
strut st_header* ph=(strut st_header*)pdata;
okay, you can do...

------解决方案--------------------
一、接收后强制转化
dest_header=(strut st_header)pdata；
二、直接内存复制
memcpy(dest_header,pdata,sizeof(strut st_header))

------解决方案--------------------
直接内存复制或者类型转换之后直接赋值