您当前的位置: value | time
25.2 | 2011-05-15 19:50:12
23.6 | 2011-05-15 19:50:58
25.8 | 2011-05-15 19:51:23
24.5 | 2011-05-15 19:51:51
关于这样结构的表，如何用linq来查
最大值：
value | time
25.8 | 2011-05-15 19:51:23
最小值：
value | time
23.6 | 2011-05-15 19:50:58
平均值
value
24.775
------解决方案--------------------
http://topic.csdn.net/u/20090329/20/10391661-1721-41c2-a9e7-f183c38254e7.html
我觉的可以参考这个
------解决方案--------------------
var max = (from x in entities orderby x.value select x).Take(1);
var min = (from x in entities descending orderby x.value descting select x).Take(1);
var avg = new { value = entities.Average(x => x.value) };
------解决方案--------------------
- C# code
void Main()
{
DataTable dt=new DataTable();
dt.Columns.Add("value",typeof(double));
dt.Columns.Add("time",typeof(string));
dt.Rows.Add(25.2,"2011-05-15 19:50:12");
dt.Rows.Add(23.6,"2011-05-15 19:50:58");
dt.Rows.Add(25.8,"2011-05-15 19:51:23");
dt.Rows.Add(24.5,"2011-05-15 19:51:51");
var max=dt.AsEnumerable().OrderByDescending(r=>r.Field<double>("value")).FirstOrDefault();
var min=dt.AsEnumerable().OrderBy(r=>r.Field<double>("value")).FirstOrDefault();
var average=dt.AsEnumerable().Average(r=>r.Field<double>("value"));
}