以下是我的xml格式
<?xml version="1.0" encoding="utf-8"?>
<Root>
<item>
<Name>terst</Name>
<Model>645</Model>
</item>
<item>
<Name>terst2</Name>
<Model>6425</Model>
</item>
</Root>
如何透過linq修改資料 ?
------解决方案--------------------
请详细看看这个帖子,介绍的很详细,LIQN对XML的增删改查基本操作
http://www.cnblogs.com/mingmingruyuedlut/archive/2011/01/27/1946239.html
------解决方案--------------------
http://download.csdn.net/detail/chaichangaini/3718057
------解决方案--------------------
- C# code
string xml = @"<?xml version='1.0' encoding='utf-8'?> <Root> <item> <Name>terst</Name> <Model>645</Model> </item> <item> <Name>terst2</Name> <Model>6425</Model> </item> </Root> "; XDocument doc = XDocument.Parse(xml); if (doc != null && doc.Root != null) { Console.WriteLine("root Name:{0}", doc.Root.Name); foreach (var item in doc.Root.Nodes()) { Console.WriteLine("\troot child Name:{0}", ((XElement)item).Name); foreach (var d in ((XElement)item).Nodes()) { Console.WriteLine("\t\tName:{0},Value:{1}", ((XElement)d).Name, ((XElement)d).Value); } } } Console.WriteLine("编辑之后"); XElement el = new XElement("item1"); ((XElement)doc.Root.Nodes().Last()).AddAfterSelf(el); if (doc != null && doc.Root != null) { Console.WriteLine("root Name:{0}", doc.Root.Name); foreach (var item in doc.Root.Nodes()) { Console.WriteLine("\troot child Name:{0}", ((XElement)item).Name); foreach (var d in ((XElement)item).Nodes()) { Console.WriteLine("\t\tName:{0},Value:{1}", ((XElement)d).Name, ((XElement)d).Value); } } } //doc.Save("fileName")