您当前的位置: #include<iostream>
using namespace std;
void show(int i)
{
int a[7];
for (i = 0;i < 7;i++)
{
cout << a[i] << endl;
}
}
void change()
{
int temp,i,j;
int a[];
while (i < j)
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
int main()
{
int num = 0;
int a[7] = {1,2,3,4,5,6,7};
show(num);
int num = 0;
change();
int num = 0;
show(num);
system("pause");
return 0;
}
我是要把 数组中的数输出后 将它们倒置 然后再输出 用函数的方法写 主函数只管调用 我只会写到这了 请问 高手帮我补充一下 修改一下呗 谢谢
------解决方案--------------------
- C/C++ code
#include<iostream>
using namespace std;
void show(int *a)
{
for (int i = 0;i < 7;i++)
{
cout << a[i] << endl;
}
}
void change(int *arr,const int length)
{
int temp =0;
int j =length-1;
for ( int i=0;i<length/2;++i,--j )
{
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
int main()
{
int num = 0;
int a[7] = {1,2,3,4,5,6,7};
show(a);
change(a,7);
cout<<"转换后....."<<endl;
show(a);
system("pause");
return 0;
}
------解决方案--------------------
- C/C++ code
#include<iostream>
using namespace std;
#define N 7
//const int N=7;
void show(int a[])
{
for (int i = 0;i < N;i++)
{
cout << a[i] << " ";
}
cout<<endl;
}
void change(int a[])
{
int temp;
for (int i = 0;i < N/2;i++)
{
temp = a[i];
a[i] = a[N-i-1];
a[N-i-1] = temp;
}
}
int main()
{
int a[N] = {1,2,3,4,5,6,7};
show(a);
change(a);
show(a);
system("pause");
return 0;
}